please show your work a solid cylindrical insulator has a radius a = 0.12m and a

Question

please show your work

a solid cylindrical insulator has a radius a = 0.12m and a uniform charge density p=.38 C/m^3. centered on the insulator is a conducting cylindrical shell of inner radius b=.37m and outer radius c=0.42m . the net charge on the conducting shell is zero , assume that each cylinder is very long compared to its radius

what is the magnitude of the electric field 0.55 m from the center of the insulating cylinder ?

what is the magnitude of the surface charge density (charge per unit area) on the outer surface of the conducting shell ?

Explanation / Answer

The strucure of the cylinder doesn't matter in case the question asks the value of the electric field outside the conducting surface, as it acts as charged line for radius > charged radius.

E=(charge density=0.38)/(2*pi*(permittivity constant=8.85*10^-12)*0.55)

gives 1.24*10^10 C/m^2

At the edge of the outer shell the charge density will still be the sme as there's no charge in between.

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