Also in part B would you use .001 or .0012 please explain why as well Hydrogen p

Question

Also in part B would you use .001 or .0012 please explain why as well Hydrogen peroxide, H202 decomposes according the following reaction: 2 H202(0)2 H20g)+0210) 2. The following were collected during a study of its decomposition at a certain temperature: time (sec 0.100 0.088 0.0700 0.051 0.025 0.006 120 600 1200 2400 Graph the concentration and time data to determine the order of the reaction with respect to hydrogen peroxide. Explain your reasoning and work. When graphing the data, gon arturved ling. Butwnguyen natur Write a rate law for this reaction, assuming that the products do not affect the rate of the reaction, and determine a rate constant with appropriate ui a. b. Wrtle arate law for this reacion, ássuming that the products do not affect the rate b. C. Calculate the half-life of the reaction d. Predict the concentration of hydrogen peroxide at a time of 8 mins

Explanation / Answer

Honestly, I don't know what is wrong with this. All seems to be ok. The reaction is actually a 1st order reaction. If you plot lnC vs t and 1/C vs t, the r2 obtained are closer to 1, but the closest is of the first order plot.

Now, in my case, I obtained the following data:
y = -1.17x10-3x - 2.2924

Now, the rate law, according to the reaction will be:
r = k[H2O2]2 --> This is because you have a 2 as coefficient that balance the reaction, that's why you have to put the 2.

Now, using the plot, the slope gives the rate constant. In this case I will use the 1.17x10-3 instead of 0.001. This is because the number obtained in scientific notation was expressed like that, and you usually take about 2 or 3 significant figures to get more accurate results.

With this value taken, the half life and concentration will change:
t1/2 = ln2 / 1.17x10-3 = 592.43 s

See the difference between taking just 0.001 and 0.00117 or 0.0012? there are more separation in time.

the concentration then:
C = 0.1 * exp(-1.17x10-3 * 8*60)
C = 0.057 M

Hope this helps

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