determine which acid is present if its concentration is 3.5M in a 250 mL solutio

Question

determine which acid is present if its concentration is 3.5M in a 250 mL solution. The mass was experimentally determined to be approximately 86 grams (sulfuric acid, phosphoric acid, chloric acid, hydrochloric acid, hydrofluoric acid) determine which acid is present if its concentration is 3.5M in a 250 mL solution. The mass was experimentally determined to be approximately 86 grams (sulfuric acid, phosphoric acid, chloric acid, hydrochloric acid, hydrofluoric acid) determine which acid is present if its concentration is 3.5M in a 250 mL solution. The mass was experimentally determined to be approximately 86 grams (sulfuric acid, phosphoric acid, chloric acid, hydrochloric acid, hydrofluoric acid)

Explanation / Answer

First of all we need to know the number of moles of solute present in 3.5M of 250 mL solution from the relation:

Molarity of solution = number of moles of solute X 1000 / volume (mL)

Now, number of moles of solute = Molarity of solution X volume / 1000

number of moles of solute = 3.5 X 250 /1000

number of moles of solute = 0.875    and w of solute = 86 g (given)

Now, we will calculate the MW of solute,

number of moles of solute = w (in gram) / MW

MW = 86/0.875

MW = 98.2

Now, check this MW value with given acids and it fits only with phosphoric acid (97.99). Hence acid is phosphoric acid,

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