determine the null and alternative hypotheses. compute the expected counts for e
ID: 3319657 • Letter: D
Question
determine the null and alternative hypotheses.
compute the expected counts for each color.
what is the test statistic: x 2
0= rounound to 3 decimal places as needed.
what is the p-value of the test? round to 3 decimals places as needed
A manufacturer of colored candies states that 13% of the candies in a bag should be brown, 14% yellow 13% re 24% lu 20 orange, and t6% gree . A stu er randomly selected a bag of colored candies. He counted the number of candies of each color and obtained the results shown in the table. Test whether the bag of colored candies follows the distribution stated above at the = 0.05 level of sgnificance. Click the icon to view the table Determine the null and alternative hypotheses. Choose the correct answer below. O A. Ho: The distribution of colors is the same as stated by the manufacturer. 0 B. Ho: The distribution of colors is not the same as stated by the manufacturer O C. None of these. H,: The distribution of colors is not the same as stated by the manufacturer H,: The distribution of colors is the same as stated by the manufacturer. i Observed Distribution of Colors Color Frequency Claimed Proportion Colored Candies in a bag Brown Yellow Red Blue Orange Green 61 64 56 628767 0.130.14 0.13 024 0.20 1-0.16 Print Done Click to select your answer and then click Check Answer parts Clear All Final CheckExplanation / Answer
Null hypothesis: Proportions of diff. colors = as claimed; SAME AS MANUFACTURER
Alternative hypothesis: Proportions of diff. colors = NOT as claimed; NOT SAME AS MANUFACTURER
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Total candies: 397
Exp counts of each color:-
1. Brown: 0.13*(397) = 51.61 = 52
2. Yellow: 0.14*(397) = 55.58 = 56
3. Red: 0.13*(397) = 51.61 = 52
4. Blue: 0.24*(397) = 95.28 = 95
5. Orange: 0.20*(397) = 79.4 = 79
6. Green: 0.16*(397) = 63.52 = 64
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Chi-square statistic for goodness-of-fit test = 15.9
p-value = 0.007
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