Hydrogen peroxide solution unknown a. Number Dinsity g/ml 3. Laboratory pressure
ID: 964753 • Letter: H
Question
Hydrogen peroxide solution unknown a. Number Dinsity g/ml 3. Laboratory pressure Torr 4. Laboratory temperature degreeC Part B. Hydrogen peroxide decomposition and oxygen collection 1. H_20_2 solution volume 2. gas volume 1. Laboratory pressure (p_tot) in atm (use A3 in eq (5))2. Laboratory temperature in Kevin (use A4 in eq (8a)) 3. Water vapor pressure a. In Torr (from Table I using A4) b. In atm (use 3a in eq(5)) 4. po_2(use p_tot =(1) and pH_2o = (3b) ub eq (29)) 5. Gas volume in L(B2 x 1 L/1000 mL) 6. mH_2o_2(use (2), (4), (5) in eq(26)) 7. m_sol ((A2b) and (Bl) in eq(27)) 8. H_2O_2 mass % (use (6) and (7) in eq(28)) Mean H_2O_2 mass % (use (8) in eq (30)) 10. Standard deviation (use (8) and (9) in eq (32))Explanation / Answer
6. molar mass of H2SO4. M = 34.0 g/mol
Mass of H2O2 can be calculaated from ideal gas equation
PV = nRT = (m / M)xRT
Trail-1:
mH2O2 = PVM / RT = (0.971 atm x 0.036 L x 34.0 g/mol) / (0.0821 L.atm.mol-1K-1 x 295.15 K)
=> mH2O2 = 0.04905 g
Trail-2:
mH2O2 = PVM / RT = (0.971 atm x 0.04 L x 34.0 g/mol) / (0.0821 L.atm.mol-1K-1 x 295.15 K)
=> mH2O2 = 0.0545 g
Trail-3:
mH2O2 = PVM / RT = (0.971 atm x 0.039 L x 34.0 g/mol) / (0.0821 L.atm.mol-1K-1 x 295.15 K)
=> mH2O2 = 0.05313 g
8: H2O2 mass %:
Trail-1: (0.04905 g / 10.1 g) x100 = 0.486 %
Trail-2: (0.0545 g / 10.1 g) x100 = 0.540 %
Trail-3: (0.05313 g / 10.1 g) x100 = 0.526 %
9: mean H2O2 mass%:
= ( 0.486 % + 0.540 % + 0.526 %) / 3 = 0.517 %
10: Standard deviation:
= 0.0280 %
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