Hydrogen peroxide reacts with iodide ions and hydronium ions to form iodine acco
ID: 478102 • Letter: H
Question
Hydrogen peroxide reacts with iodide ions and hydronium ions to form iodine according to the following equation. H_2O_2(aq) + 2 I^-(aq) + 2 H_3O^+(aq) rightarrow I_2(g) + 4 H_2O(l) The following is a proposed mechanism for the reaction. H_2O_2(aq) + I^-(aq) rightarrow HOI(aq) + OH^-(aq) slow HOI(aq) + I^-(aq) rightarrow I_2(g) + OH^-(aq) fast 2 OH^-(aq) + 2 H_3O^+(aq) rightarrow 4 H_2O(l) fast Determine the overall rate law for this proposed mechanism. (Rate expressions take the general form: rate = k. [A]^a. [B]^b.)Explanation / Answer
Among the 3 steps, first step is the slow step and it will be the rate determining step
H2O2(aq) + I-(aq) ------- > HOI(aq) + OH-(aq)
Therefore, rate =k [H2O2] [ I-]
Where, k is rate constant , [ H2O2] is concentration of H2O2 ,[I-] is concentration of I-
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