Isooctane, C8H18 is the compound of gasoline from which the term octane rating d

Question

Isooctane, C8H18 is the compound of gasoline from which the term octane rating derives. ***Three parts***

A) Write a balanced equation for the combustion of isooctane to yield carbon dioxide and water.

B) Assuming that gasoline is 100% isooctane and that the density is 0.792 g/mL, what mass of CO2 in KILOGRAMS is produced each year by the annual U.S. gasoline consumption of 4.6x10^10 L?

C) What is the volume on liters of this CO2 at STP?

**please show work so I can follow along for future understanding**

Explanation / Answer

      a)         Balanced equation for combustion of C8H18 is

              C8H18+ 12.5O2---> 8CO2 + 9H2O

b) Volume of gasoline = 4.6*1010 L   density = 0.792 g/L, mass of gasoline= 4.6*1010*0.792=3.6432*1010 gms

Molecular weight of isooctane (C8H18)= 8*12+18= 114 moles of isooctane= 3.6432*1010/114=3.195*108 moles

As per the stoichiometry , 1 mole of C8H18 produces 8 moles of CO2

3.195*108 moles of C8H18 produces   3.195*108*8=2.556*109 moles of CO2

Molecular weight of CO2= 44, mass of CO2 produced= 2.556*109*44=112.464*109 gms

c) 1 mole of any gas at STP occupies 22.4 L

2.556*109 moles of CO2 at STP produces 2.556*109*22.4=57.2544*109 L

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