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Determine whether the reactions listed below are entropy favored or disfavored u

ID: 962284 • Letter: D

Question

Determine whether the reactions listed below are entropy favored or disfavored under standard conditions. Predict how an increase in temperature will affect the value of Delta_rGdegree a. l_2(g) rightarrow 2l_(g) 13. Calculate delta_rGdegree at 25 deg C for the formation of 1.00 mol of C_2H_5OH(g) from C_2H_4(g) and H_2O(g). Use this value to calculate K_p for the equilibrium: C_2H_4(g) + H_2O rightarrow C_2H_5OH(g) Comment on the sign of Delta_rGdegree and the magnitude of K_p. 14. Write balanced equations for the following half-reactions. Specify whether each is an oxidation or reduction: a. H_2O_2(aq) rightarrow O_2(g) (in acid) b. H_2C_2O_4(aq) rightarrow CO_2(g) (in acid) c. NO_3(aq) rightarrow NO_(g) (in acid) d. MnO(aq) rightarrow MnO_2(l) (in base) 15. Balance the following redox equations. a. Cr_2O^2+(aq) + Fe^2+(aq) rightarrow Cr^2+(aq) + Fe^2+(aq) (in acid) b. Cr_2O^2+(aq) + SO^2+(aq) rightarrow Cr^2(OH)_3 + SO^2+(aq) (in acid) 16. The half-cells Sn^2+(aq) | S_n(s) and Cl_2(g)|Cl^-(aq) are linked to create a voltaic cell. a. Write equations for the oxidation and reduction half-cell reactions and for the overall cell reaction b. Which half-reaction occurs in the anode compartment, and which occurs in the cathode compartment?

Explanation / Answer

12)(a) I2(g) <----> 2I-(g)

Increase in the number of gaseous products increases the entropy.

Now, delta G = delta H - T*delta S

Thus, increase in the delta S value, decreases the delta G value

(b) 2SO2(g) + O2(g) ----> 2SO3(g)

Decrease in the number of gaseous products, decreases the value of delta S

Hence increase in the temperature,delta G value increases.

13) C2H4(g) + H2O(g) --------> C2H5OH(g)

Kp = PC2H5OH/{PC2H4*PH2O}

Kc = Kp/(R*T)n ; where n = moles of gaseous products - moles of gaseous reactants = -1

Thus, Kc = R*T*Kp

Delta G0rkn = -R*T*lnKc

14) (a) H2O2(aq) ------> O2(g) + 2H+ + 2e- (oxidation reaction as O is oxidized)

(b) H2C2O4(aq) -------> 2CO2(g) (Oxidation reaction as C is oxidized)

(c) NO3-(aq) ------> NO(g) ; (reduction reaction as N is reduced)

(d) MnO4-(aq) -----> MnO2(s) ; (reduction reaction as Mn is reduced)

15) Cr2O72-(aq) + 6Fe2+(aq) + 14H+(aq) --------> 2Cr3+(aq) + 6Fe3+(aq) + 7H2O(l)

2CrO42-(aq) + 3SO32-(aq) + 5H2O(l) ------> 2Cr(OH)3(s) + 3SO42-(aq) + 4OH-(aq)

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