1. What are the oxidation states of sulfur and fluorine, respectively, in the mo
ID: 961931 • Letter: 1
Question
1. What are the oxidation states of sulfur and fluorine, respectively, in the molecule, SF6?
2. Which reaction and statement correctly describes the electro-chemical cell shown and what voltage will be produced?
a. 2Al3+ + 3Pb+2 --> 2Al + 3Pb
b. 2Al3+ + 3Pb --> 3Pb2+ + 2Al
c. 2Al + 3Pb+2 --> 2Al3+ + 3Pb
d. 2Al + 3Pb --> 2Al3+ + 3Pb+2
a. e-‘s flow from the Al anode to the Pd cathode and nitrate ions diffuse into the Pb/Pb+2 solution.
b. e-‘s flow from the Pd cathode to the Al anode and nitrate ions diffuse into the Pb/Pb+2 solution.
c. e-‘s flow from the Al anode to the Pd cathode and nitrate ions diffuse into the Al/Al+3 solution.
d. e-‘s flow from the Pd cathode to the Al anode and nitrate ions diffuse into the Al/Al+3 solution.
a. 1.79 V
b 1.53 V
c. -1.53 V
d. -1.79 V
e. 3.06 V
3. A product–favored electrochemical reaction has:
a. ?G° = 0, E° = 0, and K >> 1
b. ?G° < 0, E° > 0, and K > 1
c. ?G° > 0, E° < 0, and K < 1
d. ?G° > 0, E° < 0, and K > 1
4. An electrochemical cell based on the following reaction has a cell voltage, E°, of 2.12 V. Which change could make the cell voltage greater than 2.12 V?
Zn(s) + Cl2(g, 1 atm) Zn2+(aq, 1 M) + 2Cl¯(aq, 1 M)
a. add more Zn(s)
b. add more Cl¯(aq) ions
c. decrease the concentration of Zn2+(aq) ions
d. decrease the partial pressure of Cl2
e. ?G° < 0, E° = 0, and K >> 1
Explanation / Answer
1) sulfur ------> +6
fluorine -------> -1
2)
correct answer : c.) 2Al + 3Pb+2 --> 2Al3+ + 3Pb
3)
answer : c. e-‘s flow from the Al anode to the Pd cathode and nitrate ions diffuse into the Al/Al+3 solution.
4)
Eo = E cathode - E anode
= -0.13 - (-1.66)
= 1.53 V
answer : b ) 1.53 V
5)
answer : b. G° < 0, E° > 0, and K > 1
6)
answer : c. decrease the concentration of Zn2+(aq) ions
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