The hydrogen atomic emission spectrum includes a UV line with a wavelength of 92

Question

The hydrogen atomic emission spectrum includes a UV line with a wavelength of 92.379 nm. Photons of this wavelength are emitted when the electron transitions to n_f = 1 as the final energy state. Is this line associated with a transition between different excited states or between an excited state and the ground state? different excited states between an excited state and the ground state What is the energy of the emitted photon with wavelength 92.379 nm? What was the initial energy state, n_i, of the electron in this transition? (Use your unrounded answer from (b).)

Explanation / Answer

since it goes from high n to low n, then this is between excited to goudn state (n= 1 is deffinitoin of ground=

b)

E = hc/WL

h = planc coksntat = 6.36*10^-34

c = speed of light = 3*10^8

WL = 92.379*10^-9

then

E = (6.36*10^-34)(3*10^8)/(92.379*10^-9) = 2.065*10^-18 J/photon

c)

2

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