How do I calculate soluability for NH4Cl (Ammonium Chloride) for the following d

Question

How do I calculate soluability for NH4Cl (Ammonium Chloride) for the following data sets? I am mostly looking for a push in the right direction and an how to do the calcualtions so I can finish the data sets. Thank you!!

1) 2g NH4Cl in 5 mL distilled water, crystalized at 25 degrees celsius

2) 2.2g NH4Cl in 5 mL distilled water, crystalized at 32 degrees celsius

3) 2.4g NH4Cl in 5 mL distilled water, crystalized at 40 degrees celsius

4) 2.6g NH4Cl in 5 mL distilled water, crystalized at 49 degrees celsius

5) 2.8g NH4Cl in 5 mL distilled water, crystalized at 72 degrees celsius

6) 3.0g NH4Cl in 5 mL distilled water, crystalized at 86 degrees celsius

Explanation / Answer

Solubility, by definition

S = mass in solutoin / volume ... normally we add the temperature we measure that since it is dependant of T

1)

S = 2/5 = 0.4 g/mL

2)

S = 2.2/5 = 0.44 g/mL

3)

S = 2.4/5 =0.48 g/mL

4)

S = 2.6/5 =0.52g/mL

5)

S = 2.8/5 =0.56 g/mL

6)

S = 3/5 =0.60g/mL

Related Questions

Navigate

• Browse (All)
• Browse H
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.