212.mg H2C2O4 250.mL 148.1mL Calculate the molarity of the student\'s sodium hyd

Question

212.mg

H2C2O4

250.mL

148.1mL

Calculate the molarity of the student's sodium hydroxide solution. Be sure your answer has the correct number of significant digits.

A chemistry student needs to standardize a fresh solution of sodium hydroxide. She carefully weighs out

212.mg

of oxalic acid

H2C2O4

, a diprotic acid that can be purchased inexpensively in high purity, and dissolves it in

250.mL

of distilled water. The student then titrates the oxalic acid solution with her sodium hydroxide solution. When the titration reaches the equivalence point, the student finds she has used

148.1mL

of sodium hydroxide solution.

Calculate the molarity of the student's sodium hydroxide solution. Be sure your answer has the correct number of significant digits.

Explanation / Answer

moles of oxalic acid = 0.212 g/126.07 g/mol = 0.0017 mols

moles of NaOH required to neutralize this acid = 2 x 0.0017 = 0.0034 mols

Volume of NaOH used = 148.1 ml

So concentration of NaOH solution = 0.0034 mols/0.1481 L = 0.023 M

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