Cyclopentadiene (C_5H_6) reacts with itself to form dicyclopentadiene (C_10H_12)

Question

Cyclopentadiene (C_5H_6) reacts with itself to form dicyclopentadiene (C_10H_12). A 0.0400 M solution of C_5H_6 is monitored as a function of time as the reaction proceeds. The following data was recorded. Use the appropriate plot of concentration vs. time to determine the order of the reaction with respect to C_5H_6. Include all plotted data in the report. Based on the plotted data, the reaction is (zero, first, second, choose one) with respect to C_5H_6. Determine the rate constant for the reaction.

Explanation / Answer

b)

try for second order reaction.

Ao = initial concentration= 0.040 M

At = after time t concentration

suppose at 50 sec At = 0.03M and at 100 sec At = 0.024 M

k = 1/t [1/At - 1/Ao]

k = 1/50 [1/0.03- 1/0.04]

k = 0.167 M-1s-1

rate constant = k = 0.167 M-1s-1

similarly try at 100 sec

k = 1/100 [1/0024 - 1/0.04]

k = 0.167 M-1s-1

so

rate constant = k = 0.167 M-1s-1

c)

use above equation.

now time = 350 sec

0.167 = 1/350 [1 / At - 1/0.04]

At = 0.012 M

concentration fo C5H6 after 350 sec = 0.012 M

note : for part a

please try to plot a graph in between 1 /At verses time

1 / At means at 50 sec , 1/ 0.03

                     at 100sec , 1/ 0.024

                   at 150 sec , 1/ 0.02

                    at 200 sec , 1/0.0174

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