Experimental Procedure 1. Obtain 60 mL of 0.1 M HCl, hydrochloric acid solution.

Q: Experimental Procedure 1. Obtain 60 mL of 0.1 M HCl, hydrochloric acid solution.

M1V1 = M2V2 0.1*5 = M2*50 M2 = 0.1*5/50 = 0.01 M Original concentration of HCl = 0.1 M Volume of HCl = 5 mL

ID: 959234 • Letter: E

Question

Experimental Procedure

1. Obtain 60 mL of 0.1 M HCl, hydrochloric acid solution.

2. Using a clean, dry graduated cylinder, transfer 50 ml of this solution into a clean 100 or 150 mL beaker. Label the beaker with the concentration of the acid.

3. Pipette 5 mL of the remaining acid solution into a clean 50 or 100 mL graduated cylinder. The graduated cylinder only needs to be rinsed with distilled water.

4. Dilute the 5 mL of HCl to 50 mL with distilled water in the graduated cylinder.

What is the original concentration Hcl and volume HCl used in dilution?

Explanation / Answer

M1V1 = M2V2

0.1*5 = M2*50

M2 = 0.1*5/50

= 0.01 M

Original concentration of HCl = 0.1 M

Volume of HCl = 5 mL

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Experimental Procedure 1. Obtain 60 mL of 0.1 M HCl, hydrochloric acid solution.

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Explanation / Answer

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