Experiment data are as following: A-weight of test tube: 20g B-Weight of test tu

Question

Experiment data are as following:

A-weight of test tube: 20g

B-Weight of test tube +naphthalene : 45g

C-weight of naphthalene:_________

D-weight of paper: .85g

E-weight of paper + Phosphorus: 1.59g

F-weight of phosphorus: _________

If the melting point of a pure solvent is 78.5 C and the melting point of the pphosphorus solution becomes 76.85 C what is the correct formula weight of phosphorus and what is the correct formula for phosphorus? Kf= 6.9C/m for naphthalene solvent

(Naphthalene is solvent, phosporus is the solute)

Explanation / Answer

weight of naphthalene = 45-20 = 25 g

weight of Phosphorus = 1.59-0.85 = 0.74g

delta T = kf*m

m = (78.5-76.85)/6.9 = 0.239

(0.74*1000/x*25) = 0.239

x = 123.85 approximately equal to 124

124/31 = 4

so formula is P4

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