How do i do the math so that i can complete the table below for the final concen

Question

How do i do the math so that i can complete the table below for the final concentration in 1 ml reaction and volume needed for cocktail of 5.5 samples?

presented in the handout does not necessarily match the numbering of the cultures. Follow only the activity assay protocol corresponding to your protein. Be sure to address the Conclusion questions (page 34) and include in your notebook. Activity assay A 1. In a 15 ml conical tube, prepare (and mix by inversion) 5.5 samples of assay cocktail (5 samples, plus a little extra to cover pipetting error) with the following composition (per sample) Volume needed Volume per Stock reagent for cocktail of reaction Final concentration in 1ml reaction 5.5 samples 900 1 25 | 0.1 M potassium phosphate buffer pH 6.5 | 40 mM 1-chloro-2,4-dinitrobenzene (CDNB)- toxic, wear gloves! S0 100 mM glutathione (reduced | 100 mM glutathione (reduced) 50 1 Reproduce the completed table shown above in your notebook. the assay cocktail, then pipette 25 ul of bugbuster reagent 2. Into five cuvettes, pipette 975 1 of or the appropriate bacterial extract (from table shown below) to the corresponding cuvette, and mix by pipetting up and down several times.

Explanation / Answer

1) stock reagent no 1=0.1M potassium phosphate buffer

Moles of reagent added in the reaction=volume*molarity=900*10^-6 L*0.1 mol/L=9*10^-5 moles

Final conc in 1 ml reaction=moles/volume= 9*10^-5 moles/1ml=9*10^-5 moles/10^-3 L=9*10^-2 moles/L=0.09M

Or, Final conc in 1 ml reaction=0.09M

2)stock reagent=40mM CDNB

Moles of reagent added in the reaction=(40*10^-3 mol/L)*(25*10^-6 L)=10^-6 moles

Final conc in 1 ml reaction=10^-6 moles/1ml=10^-6 moles/10^-3L=10^-3 M

3)stock reagent=100mM glutathione

Moles of reagent added in the reaction=100*10^-3 mol/L * (50 *10^-6 L)=5*10^-6 moles

Final conc in 1 ml reaction=5*10^-6 moles/1ml=5*10^-6 moles/10^-3 L=5*10^-3 mol/L=0.005 M

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