The K_ eq for imidazole binding to hemoglobin can be determined from the followi
ID: 956240 • Letter: T
Question
The K_ eq for imidazole binding to hemoglobin can be determined from the following linear equation: 1/del A_100 K_eq times 1/[Im] + 1/del A_100 = (1/del A) For the plot of the reciprocal of the change in absorbance versus the reciprocal of the imidazole concentration, identify the equivalent of the slope and the y-intercept in the above equation. Copy the equation in your notebook, and clearly mark a square around the term equivalent to slope and a circle around the y-intercept. If the best-fit line determined for a set of data gives a slope of 0.043 M and an intercept of 19, what is the value of del A100 and K_ eq? For the reaction, Hb Fe^+(aq) + Im(aq) implies Hb Fe - Im^+(aq), what does the calculated value of K_ eq from question 3b predict for the favorability of reactants or products?Explanation / Answer
A) the plot is for the reciprocal of the absorbance 1/DA vs the reciprocal of the imidazole concentrstion 1/[Im]. This means that y=1/DA and x=1/[Im]. So looking at the equation we can say that the intercept is 1/DA100 and the slope is 1/DA100xKeq.
B) 1/DA100= 19 ---> DA100= 0.053
0.043M= 1/DA100xKeq =1/0.053xKeq
Keq= 4.39x102
c) The value of Keq is big, that means that the reaction is going to be really favorable in the way it is written. Just for you to know, when Keq=1 neither products nor reactants are favoured, when Keq>1 (this case), products are favoured, and when Keq<1 reagents are favoured.
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