Question 1 In Part IIB, neutralization of acetic acid and NaOH, what is the limi

Question

Question 1

In Part IIB, neutralization of acetic acid and NaOH, what is the limiting reactant of the neutralization reaction?

Question 2

A sample of solid X was dissolved in 200. g of water at 20. C. If the final temperature of the solution was 15. C, which one if true about the dissolution of X in water?

Question 3

Specific heat capacity of water is 4.184 J/(g C). What is its molar heat capacity?

Question 4

In a coffee-cup calorimeter, 50.0 g hot water at 60.0 C was mixed with 50.0 g cold water at 20.0 C. If the final temperature is 39, what is the heat capacity of the calorimeter in J/C? Specific heat of water is 4.184 J/(g C)

Question 5

Students used two thermometers in Thermo lab. If both thermometers consistently read temperature exactly 1.0 degree higher than the actual temperature, how does this affect the experimental molar heat of neutralization?

Question 6

A substance has a molar heat of solution of - 1000 kJ/mol. What is correct if 0.5 mol of this substance is dissolved in water?

Question 7

Green line of Hg lamp has a wavelength of 546.1 nm. What is the energy of photon associated with this green line?

Question 8

According to Bohr's Model, which one is correct about a transition from n=2 to n=1 in a hydrogen atom?

Question 9

The lines observed in H-lamp are parts of Balmer Series. All these lines are due to a transition from various higher n value to a common n. What is this common lower n value for all these lines? (Hint: the information can be found around "Calculations" area on page 8-67)

Question 10

Since we can only see visible lines from a hydrogen lamp, hydrogen lamp does not produce any UV light.

Explanation / Answer

2. Endothermic with positive heat of solution

3. Specific heat capacity of water is 4.184 J/(g C)

   molar heat capacity = s*Mwt

      = 4.184*18 = 75.312 j/mol.c

4.

heat lost by hot water = heat gained by cold water + calorimeter

50*4.184*(60-39) = 50*4.184*(39-20)+x*(39-20)

x = heat capacity of calorimeter = 22 j/C

5. Since the temperature differences are used in all caculations, this should not affect the molar heat of neutralization

6. 500 kJ of heat will be released by the substance

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