Question 1 How would you classify reaction Eq. 5-2? (eq 5-2 is calcium + water -

Question

Question 1

How would you classify reaction Eq. 5-2? (eq 5-2 is calcium + water --> hydrogen+calcium hydroxide)

neutralization

oxidation-reduction

precipitation

disproportionation

Question 2

In Eq. 5-3, calcium hydroxide is classified as, (Eq. 5-3 is calcium hydroxide + hydrochloric acid --> water + salt)

an acid.

a reductant.

an oxidant.

a base.

Question 3

Which is the correct balanced equation for Eq. 5-2?

2Ca(s) + 2H2O(l) ? H2(g) + 2CaOH(aq)

Ca(s) + H2O(l) ? H(g) + CaOH(aq)

Ca(s) + 2H2O(l) ? H2(g) + Ca(OH)2(aq)

Ca(s) + 2H2O(l) ? 2H(g) + Ca(OH)2(aq)

Question 4

Which is the correct balanced equation for Eq. 5-3?

Ca(OH)2(aq) + 2HCl(aq) ? 2H2O(l) + CaCl2(aq)

CaOH(aq) + HCl(aq) ? H2O(l) + CaCl(aq)

Ca(OH)2(aq) + 2HCl(aq) ? H3O+(l) + CaCl2(aq)

Ca(OH)2(aq) + HCl(aq) ? H2O(l) + CaCl2(aq)

Question 5

What is the stoichiometric relation between calcium hydroxide and hydrocloric acid in Eq. 5-3?

1:1

3:1

1:2

2:1

neutralization

oxidation-reduction

precipitation

disproportionation

Explanation / Answer

1) oxidation-reduction

2) a base.

3) Ca(s) + 2H2O(l) ? H2(g) + Ca(OH)2(aq)

4) Ca(OH)2(aq) + 2HCl(aq) ? 2H2O(l) + CaCl2(aq)

5) 1:2

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