Propane (C3H8) is to be burned with air. Determine the stoichiometric ratio of a

Question

Propane (C3H8) is to be burned with air.

Determine the stoichiometric ratio of air to propane for complete combustion to CO2 and water.

If 10 mol propane per second are fed with 20% excess air, determine the molar flowrate and composition of the product gases under the following conditions:

     - 95% conversion of propane

     - No carbon monoxide produced

Solve using mole balances.

Propane (C_3H_8) is to be burned with air. Determine the stoichiometric ratio of air to propane for complete combustion to CO_2 and water. If 10 mol propane per second are fed with 20% excess air, determine the molar flowrate and composition of the product gases under the following conditions: 95% conversion of propane No carbon monoxide produced Solve using mole balances.

Explanation / Answer

C3H8 + 5O2 -----> 3CO2 + 4H2O

for complete combustion of each mole of propane, moles of O2 required = 5

Moles of propane present per second = 10 moles

Moles of propane converting = 0.95*10 = 9.5

Thus, moles of O2 required = 5*9.5 = 47.5

Thus, moles of air required = 5*moles of O2 = 237.5

Since air is supplied 20% more than the requirement, thus, moles of air fed per second = 1.2*237.5 = 285

Moles of propane in the product = 0.5

moles of O2 in the product = (285/5) - 47.5 = 9.5

moles of N2 = 228

Moles of CO2 = 3*moles of propane reacted = 28.5

moles of H2O = 4*moles of propane reacted = 38

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