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A voltaic cell contains two half-cells. One half-cell contains a nickel electrod

ID: 955548 • Letter: A

Question

A voltaic cell contains two half-cells. One half-cell contains a nickel electrode immersed in a 1.00 M Ni(NO3)2 solution. The second half-cell contains a titanium electrode immersed in a 1.00 MTi(NO3)3 solution.

Ered = 0.257 V

Ered= 1.370 V

(a) Using the standard reduction potentials given above, predict the standard cell potential of the voltaic cell.
____V

(b) Write the overall balanced equation for the voltaic cell. (Include states-of-matter under the given conditions in your answer.)

Ni2+(aq) + 2 e Ni(s)    

Ered = 0.257 V

Ti3+(aq) + 3 e Ti(s)    

Ered= 1.370 V

Explanation / Answer

a) Given that:

Ni2+(aq) + 2e- Ni(s); Eored = -0.257 V    

Ti3+(aq) + 3e- Ti(s); Eored = -1.370 V    

Reduction half reaction is: Ni2+(aq) + 2e- Ni(s); Eored = -0.257 V    

Oxidation half reaction is: Ti(s) Ti3+(aq) + 3e- ; Eoox = - Eored = -( -1.370 V)    

Standard cell potential for voltaic cell is given by:

Eocell = Eored + Eoox

Eocell = (-0.257 V) + (1.370 V) = 1.113 V

b) Overall balanced equation for the voltaic cell: Ni2+(aq) +Ti(s) Ni(s) + Ti3+(aq)

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