A voice signal is measured at 3.21692 V and it resides inside an interval from 3

Question

A voice signal is measured at 3.21692 V and it resides inside an interval from 3.20 V to 3.30 V. a)How big is a single interval in volts? c) Receivers have no choice but to decode the the binary sample value at the center of the interval. So, what would the received voltage of the sample be? d) If the total range of voltages started at zero and there are 512 intervals, what would the maximum possible voltage be? e) The original voice signal voltage and the decoded voltage value are different. What is this "round off error"? f) What is the ratio of received voltage to round off error in absolute and in dB form? This is signal to noise ratio for this digital system.

Explanation / Answer

a) 0.10 V is the measurement of a single interval in volts. b) 9 bits are represented if the above sample had 512 levels. c) 3.25 V would be the received voltage of the sample. d) 51.2 V would be the maximum possible voltage if the total range of voltages started at zero and there are 512 intervals. e) 0.03308 is the “round off error” (quantization error). f) 98.25 is the ratio of received voltage to round off error in absolute form. 19.92 is the dB form.

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