The pH of a 0.220 McSHscooH solution is 2.42. (a Write the ionization constant e

Question

The pH of a 0.220 McSHscooH solution is 2.42. (a Write the ionization constant expression for an aqueous solution of benzoic acid. (b) Calculate Ka for benzoic acid. (c) Determine the percent ionization of benzoic acid. HOBr For a 0.033 M HOBr solution, Ka is 2.5 X10 (a Write an equation for the ionization constant ofHoBr (b) Determine the hydrogen ion concentration of this solution (c) Calculate the pH ofthe solution (d) Calculate the percent ionization of the acid In a different experiment, o 010M NaoH is added to the initial acid solution. Assume no change in volume. Calculate the (e) hydrogenion concentration of this solution. pH of the solution (go percent ionization of the acid 3. Sodium ascorbate, C6HrooNa, readily dissolves in water, according to the following equation: The ascorbate ion reacts with water in the following reaction:

Explanation / Answer

3. Sodium ascorbate is a basic salt.

Na+(aq) is the conjugate acid of a strong base, so it is neutral. C6H7O6-(aq) is the conjugate base of a weak acid (HC6H7O6), so it is a weak base. C6H7O6-(aq) has the ability to accept one hydrogen atom. So C6H7O6Na is a weak base.

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