A sample of propane gas (C_4H_10) has a volume of 13.47 L at 25degreeC and 1 atm

Question

A sample of propane gas (C_4H_10) has a volume of 13.47 L at 25degreeC and 1 atm pressure. What volume will it occupy at 50.degreeC and 1 atm pressure? 6. A sample of neon gas occupies 100.0 mL at 100.0degreeC. The sample is then heated to 200.0degreeC. What is the new volume of neon (pressure remains constant)? 7. A sample of chlorine gas (Cl_2) gas occupies 95.7 mL at-11.5degreeC. Heating at constant pressure chanses its volume to 146.4 mL. What is the new temperature in Kelvin and in Celsius?

Explanation / Answer

5)

PV = nRT

pressure is constant

so

V1 / T1 = V2 / T2

given

V1 = 13.47

T1 = 25 + 273 = 298 K

T2 = 50 + 273 = 323 K

so

13.47 / 298 = V2 / 323

V2 = 14.6

so

the gas will occupy 14.6 L at 50 C

6)

V1 = 100

T1 = 100 + 273 = 373 K

T2 = 200 + 273 = 473 K

so

100 / 373 = V2 / 473

V2 = 126.81

so

the new volume is 126.81 ml

7)

given

V1 = 95.7

T1 = -11.5 + 273 = 261.5 K

V2 = 146.4

so

95.7 / 261.5 = 146.4 / T2

T2 = 400 K

T2 = 400 - 273

T2 = 127 K

so

the new temperature is 400 K and 127 K

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