27, 28, 29 please show how you came to your answer EXTRA CREDIT 27, K, for the r

Question

27, 28, 29
please show how you came to your answer

EXTRA CREDIT 27, K, for the reaction: NILCI(s) e, IICHg) + NHO is 1.04 x 103 atr. If 1.00 mole of NH4Cl(s) is placed in an prcesure of iCl,in am,at equilibrtum HINT. l the amunt of N evacuated flask, what is the partial pressure of HCL, in atm, at equilibrium? [HINT: Is the amount of NI important? In the evacuated flask NIL-Cl(s) decomposes.] A. 0.51 B. 0.76 02 D. 0.204 E. not enough information given ya is 28. If the equilibrium constant for A + B-C is 0.123, then the oquilibrium constant for we'A + 29, For the hypothetical reactions l and 2 below, K.-1.00 x 10 , and K.-1.00 x 10 constant for WC e, A + ½B is I. AB: e A+2B 2. A+Be AB 3. AB, e AB+B The value of K for reaction 3 would be

Explanation / Answer

            NH4Cl <----> NH3 + HCl
initially   1              0     0
At equi    1-x                 x     x
Kp = (P of NH3)*(P of HCl) / (P of NH4Cl)
1.04 * 10^-2 = x*x / (1-x)
x = 0.0969 = P of HCl

A + B ----> C K1 = 0.123
C -----> A + B K2 = 1/K1 = 1/ 0.123 = 8.13
1/2 C ----> 1/2 A + 1/2 B K3 = (K2)^1/2 = (8.13)^1/2
K3 = 4.065

AB2 ----> A + 2B K1 = 1 * 10^-5
A + B ----> AB   K2 = 1 * 10^-3
adding above two equations then,
AB2 ------> AB + B K3 = K1 * K2 = 10^-5 * 10^-3 = 10^-8

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