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19, 20, 21, and 22 please show how you came to that answer 19. Consider the foll

ID: 954233 • Letter: 1

Question


19, 20, 21, and 22
please show how you came to that answer

19. Consider the following reaction: A(g)+2Bg) 20)+D) A and B, 1.50 mol each, are placed in a 5.0 liter coetainer. Aßer equilibrium has been established, 0 50 mol of Dis present in the container Calculate the equilibrium constant, K.. for this reaction A. 1.00 B. 0.15 C. 0.33 D. 3.0 E none of these 20. Which of the following actions changes the value of the qquilibrium constant for the reaction HXg) + ls(g) e2g E. changing the temperature 21. For the following reactions occurring at s0o K, arange them in order of increasing tendency to procted to completion A adding more H D. using an enzyme B. removing some HI C using a catalyst (least

Explanation / Answer

19.

with D = 0.5 mol

equilibrium concentrations for,

[A] = (1.5 - 0.5) mol/5 L = 0.2 M

[B] = (1.5 - 1.0) mol/5 L = 0.1 M

[C] = 1.0 mol/5 L = 0.2 M

[D] = 0.5 mol/5 L = 0.1 M

Equilibrium constant K = [C][D]/[A][B] = (0.2 x 0.1)/(0.2 x 0.1) = 1.0

So the answer would be,

A. 1.00

20. The factor that would change the equilibrium constant for the reaction is,

E. changing the temperature

K depends on temperature and is independent of concentrations.

21. The tendency of reaction to proceed to completion has the folowing order,

C. 2 < 3 < 1

Higher the Kp greater would be the tendency for competion.

22. The equilibrium concentration of Cl2 and I2 would be,

A. 1.0 x 10^-2 M

2ICl ---> I2 + Cl2

initial [ICl] = 1 mol/1 L = 1 M

let x be the change at equilibrium,

Kp = 1 x 10^-4 = x^2/(1 - x)

x^2 + 2 x 10^-4x - 1 x 10^-4 = 0

x = 1.0 x 10^-2 M

So, [I2] = [Cl2] = 1 x 10^-2 at equilibrium

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