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Use the References to access important values if needed for this question. Compa

ID: 953101 • Letter: U

Question

Use the References to access important values if needed for this question. Compare the de Broglie wavelength of a baseball 1.30x10 miles per hour (5.81x10° m/s) and a golf ball with a speed of 70.0 miles per hour (31.3 m/s) moving at 90.0 miles per hour (40.2 m/s) to that of an electron moving at Louis de Broglie Which region of the electromagnetic spectrum are each of these wavelengths near? A. Ultraviolet 10 to 10 meters B. X-ray C. Gamma ray to 10 meters D. Smallerthan meters. Cannot detect wave-like properties. Only particle-like behavior will be observable. 101 to 108 meters c. Gamma ray 10 to 10' meters Particle Mass (kg) Velocity (m/s) Wavelength (m) Region baseball electron 9.11x10 5.81x10 golf ball 4.50x102 Particle 0.140 40.2 31.3 Submit Answer Nod

Explanation / Answer

Particle : Baseball

kinetic energy (E) = (1/2)mv^2

Feed m = mass and v = velocity from above

E = (1/2) x 0.140 x (40.2)^2 = 113.123 J

wavelength (l) = h/p = h/sq.rt.(2Em)

h = planck's constant

wavelength of particle = 6.626 x 10^-34/sq.rt.(2 x 0.140 x 113.123) = 1.18 x 10^-34 m

Region : Particle like behavior only.

Particle : Electron

kinetic energy (E) = (1/2)mv^2

Feed m = mass and v = velocity from above

E = (1/2) x 9.11 x 10^-31 x (5.81 x 10^6)^2 = 1.54 x 10^-17 J

wavelength (l) = h/p = h/sq.rt.(2Em)

h = planck's constant

wavelength of particle = 6.626 x 10^-34/sq.rt.(2 x 9.11 x 10^-31 x 1.54 x 10^-17) = 1.25 x 10^-10 m

Region : X-ray

Particle : Golf ball

kinetic energy (E) = (1/2)mv^2

Feed m = mass and v = velocity from above

E = (1/2) x 4.50 x 10^-2 x (31.3)^2 = 22.04 J

wavelength (l) = h/p = h/sq.rt.(2Em)

h = planck's constant

wavelength of particle = 6.626 x 10^-34/sq.rt.(2 x 4.50 x 10^-2 x 22.04) = 4.70 x 10^-34 m

Region : Particle like only

Particle : Bullet

kinetic energy (E) = (1/2)mv^2

Feed m = mass and v = velocity from above

E = (1/2) x 1.90 x 10^-3 x (31.3)^2 = 0.931 J

wavelength (l) = h/p = h/sq.rt.(2Em)

h = planck's constant

wavelength of particle = 6.626 x 10^-34/sq.rt.(2 x 1.90 x 10^-3 x 0.931) = 1.11 x 10^-32 m

Region : Particle like only