The ions react according to the following reactions: H_2O_2 + 2I^- + 2H^+ implie

Question

The ions react according to the following reactions: H_2O_2 + 2I^- + 2H^+ implies I_2 + 2H_2O...slow I_2 + S_2O^2- _3 implies 2I^- + S_4O^2- _6...fast H_2O_2 + 2S_2O^2- _3 + 2H^+ implies 2H_2O + S_4O^2- _6...overall If the concentration of I^- is increased, then the rate of the reaction would (increase, decrease)? If a catalyst is added to the reaction, the rate of the reaction would (increase, decrease)? If the temperature of the reaction is decreased, the rate of the reaction would (increase, decrease)?

Explanation / Answer

1. Decrease, you are pushing the slower reaction forward but the fastest in the opposite direction.

2.Decrease, You are pushing the reaction to the left

3. Increase, you reduce the activation energy, thus the rate is lower.

4. Decrease, usually at lower temperatures reactions are slower.

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