Part A Calculate the enthalpy change, ?H, for the process in which 13.1 g of wat

Q: Part A Calculate the enthalpy change, ?H, for the process in which 13.1 g of wat

Part A q absorbed = m*swater*DT + n*DHvap = 13.1*4.18*(25-2.2) + (13.1/18)*44*10^3 = 33.27 kj DH = 33.27 kj part B q absorbed = m*s*DT +n*DHfus + m*s*DT 5.92*10^3*10^3 = x*2.01*(0+12.5) + (x/18)*6.01*10^3 + x*4.18*(18.4-0) x = mass of ice,water = 13580.3 grams

ID: 948751 • Letter: P

Question

Part A Calculate the enthalpy change, ?H, for the process in which 13.1 g of water is converted from liquid at 2.2 ?C to vapor at 25.0 ?C . For water, ?Hvap = 44.0 kJ/mol at 25.0 ?C and Cs = 4.18 J/(g??C) for H2O(l).

Part B

How many grams of ice at -12.5 ?C can be completely converted to liquid at 18.4 ?C if the available heat for this process is 5.92×103 kJ ?

For ice, use a specific heat of 2.01 J/(g??C) and ?Hfus=6.01kJ/mol.

« previous | 28 of 53 | next Part A Enthalpy of a Phase Change Calculate the enthalpy change, AH, for the process in which 13.1 g of water is converted from liquid Heat, q, is energy transferred between a system and its surroundings. For a process that involves a temperature change at 2.2 °C to vapor at 25.0 °C For water, ,ap-44.0 kJ/mol at 25.0 °C and Cs = 4.18 J/(g-°C) for H20(1) Express your answer to three significant figures and include the appropriate units where Cs is specific heat and m is mass Heat can also be transferred at a constant temperature when there is a change in state. For a process that involves a phase change where, n is the number of moles and H is the Submit Hints My Answers Give Up Review Part enthalpy of fusion, vaporization, or sublimation The following table provides the specific heat and Incorrect; Try Again enthalpy changes for water and ice Specific heat Substance J/(g. °C)(kJ/mol 4.18 2.01 Part B water 44.0 How many grams of ice at -12.5 C can be completely converted to liquid at 18.4 °C if the available heat for this process is 5.92x103 kJ For ice, use a specific heat of 201 J/(g-°C) and Hfs-6.01k//mol Express your answer to three significant figures and include the appropriate units ice 6.01 keyboard shortcuts 13.6 Submit Hints My Answers Give Up Review Part Incorrect; Try Again

Explanation / Answer

Part A

q absorbed = m*swater*DT + n*DHvap

= 13.1*4.18*(25-2.2) + (13.1/18)*44*10^3

= 33.27 kj

DH = 33.27 kj

part B

q absorbed = m*s*DT +n*DHfus + m*s*DT

5.92*10^3*10^3 = x*2.01*(0+12.5) + (x/18)*6.01*10^3 + x*4.18*(18.4-0)

x = mass of ice,water = 13580.3 grams

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Part A Calculate the enthalpy change, ?H, for the process in which 13.1 g of wat

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