Part A At 800 K, the equilibrium constant for the reaction A2(g)-2A(g) is Ke = 3

Question

Part A At 800 K, the equilibrium constant for the reaction A2(g)-2A(g) is Ke = 3.1 × 10-4 You may want to reference Chapter 15 while completing this problem Assuming both forward and reverse reactions are elementary reactions, which rate constant do you expect to be larger, k or kr? (Pages 622-663) Match the words in the left column to the appropriate blanks in the sentences on the right. Reset Help much less than K,=kr/k, and the value of Kc is zero (3.1 x 10-4). The value of kr larger much less than one much more than must be than the value of kr one smaller much more than zero Submit Request Answer Part B

Explanation / Answer

A.

Kc = 3.1 * 10-4

Since Kc is smaller than 1,

kf < kr

So, kr is larger.

B.

Kc = kf / kr

3.1 * 10-4 = 0.47 / kr

kr = 1.52 * 103 s-1

C.

The forward eaction is bond breaking which is always endothermic.

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