Part A An 12 mH solenoid inductor is wound on a form 0.80 m in length and 0.10 m
ID: 1568380 • Letter: P
Question
Part A
An 12 mH solenoid inductor is wound on a form 0.80 m in length and 0.10 m in diameter. A coil is tightly wound around the solenoid at its center. The coil resistance is 5.8 ohms. The mutual inductance of the coil and solenoid is 53 H. At a given instant, the current in the solenoid is 610 mA, and is decreasing at the rate of 2.5 A/s. At the given instant, the induced emf in the solenoid is closest to:
An 12 mH solenoid inductor is wound on a form 0.80 m in length and 0.10 m in diameter. A coil is tightly wound around the solenoid at its center. The coil resistance is 5.8 ohms. The mutual inductance of the coil and solenoid is 53 H. At a given instant, the current in the solenoid is 610 mA, and is decreasing at the rate of 2.5 A/s. At the given instant, the induced emf in the solenoid is closest to:
27 mV 30 mV 24 mV 33 mV 21 mVExplanation / Answer
Given that,
inductance L = 12 mH
di / dt = 2.5 A/s
lnduced emf in the solenoid is,
E = L*di / dt
E = 12*10^(-3) * 2.5
E = 30 mV
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