Part A A small plastic bead has been charged to -19 nC What is the magnitude of

Question

Part A A small plastic bead has been charged to -19 nC What is the magnitude of the acceleration of a proton that is 1.2 cm from the center of the bead? Express your answer to two significant figures and include the appropriate units 2.60-1014m Submit × Incorrect; Try Again: 5 attempts remaining | Part B In which direction does the acceleration vector point? towards the bead away from the bead Correct Part C What is the magnitude of the acceleration of an electron that is 1.2 cm from the center of the bead? Express your answer to two significant figures and include the appropriate units. aVaue Units

Explanation / Answer

let Q = -19 nC = -19*10^-9 C

qp = 1.6*10^-19 C

mp = 1.67*10^-27 kg

Force acting on proton F = k*Q*qp/r^2

mp*a_p = k*Q*qp/r^2

a_p = k*Q*qp/(r^2*mp)

= 9*10^9*19*10^-9*1.6*10^-19/(0.012^2*1.67*10^-27)

= 1.14*10^14 m/s^2

B) towards the bead

C) a_e = k*Q*qe/(r^2*me)

= 9*10^9*19*10^-9*1.6*10^-19/(0.012^2*9.1*10^-31)

= 2.08*10^17 m/s^2

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