Please answer 1 & 3 below. For question 3 below (part 1 refers to Dipole moment;

Question

Please answer 1 & 3 below.

For question 3 below (part 1 refers to Dipole moment; part II refers to soluble in water; part III densisity of unknown relative to water)

Questions 1. Explain how you would accurately determine the density of an ungraiw nowu ou would accurately determine the density of an unknown liquid. 3. Assume you find four bottles in an empty laboratory, each containinga liquid. The labels that were on these bottles have fallen off and are strewn about the bench top. Therefore, you know the contents of the four bottles, but do not know which bottle belonged to which compound. The names on the labels are: trans-1,2-dichloroethylene, cis-1,2-dichloroethylene, cy clooctane, and acetic acid. Without determining the boiling point, would you be able to identify the contents of each bottle using information obtained from Parts I to III of this experiment? Explain your reasoning.

Explanation / Answer

1. First we measure the mass of a graduated measuring jar . Then fill it with exactly known volume of liquid and then find the mass again.

Mass of liquid = mass of jar with liquid - mass of empty jar.

density = mass of liquid/ volume

3. the four compounds are trans 1,2 -dichloroethylene, cis-1,2-dichloroethylene, cyclooctane and acetic acid.

Of all these four acetic acid is the most polar hence is soluble(miscible) in water (solubility) while the others are insoluble.

cyclooctane is least polar of the four , and it is a hydrocarbon thus it will be lighter than water , less dense than water.

CIs and trans isomers of 1,2 -dichloroethylenes are heavier than water due to their high molecular weight , that is have higher density than water.

The two isomers can be identified based on their dipolemoments. The cis isomer has more dipolemeoment whereas the trans isomer has zero dipolemoment.

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