Please answer 005 only because i did answer the rest This print-out should have
ID: 3164104 • Letter: P
Question
Please answer 005 only because i did answer the rest This print-out should have 8 questions Multiple-choice questions may continue on the next column or page - find all choices before answering. Part B is worth 0 its - it is optional. give it a try to nor if you ran figure it out, but don't worry if you can't A revolutionary war cannon, with a mass of 2180 kg, firm a 18.9 kg hall horizontally. The cannonball has a speed of 134 m/s after it has left the barrel. The cannon carriage is on a flat platform and is free to roll horizontally. What is the speed of the cannon immediately after it was fired? Answer in units of m/s. The same explosive charge is used, so the total energy of the cannon plus cannonball system remains the same. Disregarding friction, how much faster would the hall travel if the cannon were mounted rigidly and all other parameters remained the same? Answer in units of m/s. A car with mass 1141 kg, moving at 16 m/s. strikes a(n) 2916 kg car at rest. If the two cars stick together, with what speed do they move? Answer in units of m/s. A(n) 3.62 kg sphere makes a perfectly inelastic collision with a second sphere that is initially at rest. The composite system moves with a speed equal to one-third the original speed of the 3.62 kg sphere. What is the mass of the second sphere? Answer in units of kg. A puck of mass 7 kg moving at 3 m/s strikes an identical puck that is stationary on friction loss ice. After the collision, the first puck leaves with a speed of v_1 at an angle of 43.8213 degree with respect to its original line of motion and the second puck leaves with a speed of v_2 at 46.1787 degree. Find v_1. Answer in units of m/s. Given: Two masses (M_1 and M_2) are a system. Let E = K + U be the total mechanical energy of the system and p be the total momentum of this system. A mass m_1 slides on a frictionless horizontal plane and collides and sticks to a mass m_2 that is at the bottom of a friction less ramp. What is conserved in the collision? Both E and p are conserved in the collision. E is conserved in the collision. Neither E nor p is conserved in the collision. p is conserved in the collision. After the collision, masses m_1 and m_2 slide together up the curved ramp and come to a rest. What is conserved during this motion?Explanation / Answer
Mass m = 7 kg
u = 3 i
M = 7 kg
U = 0
v1 = v1 cos 43.8213 i + v1 sin 43.8213 j
= 0.7215 v1 i + 0.69241 v1 j
v2 = v2 cos 46.1787 i +v2 sin 46.1787 (-j)
= 0.69241 v2 i - 0.7215 v2 j
From law of conservation of momentum ,
mu +MU = m(0.7215 v1 i + 0.69241 v1 j)+M(0.69241 v2 i - 0.7215 v2 j)
m(3i) +m(0) = m(0.7215 v1 i + 0.69241 v1 j)+m(0.69241 v2 i - 0.7215 v2 j)
3i = 0.7215 v1 i + 0.69241 v1 j+0.69241 v2 i - 0.7215 v2 j
Compare j components you get ,
0.69241 v1 -0.7215 v2 = 0
v1 = 1.042 v2 -------------( 1)
Compare i components you get ,
3 = 0.7215 v1 +0.69241 v2
= 0.7215(1.042v2) + 0.69241 v2
= 1.44422 v2
v2 = 2.077 m/s
v1 = 1.042 v2
= 1.042(2.077)
= 2.164 m/s
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.