A student gets the following data for the Heat Capacity of her calorimeter. Mass
ID: 948190 • Letter: A
Question
A student gets the following data for the Heat Capacity of her calorimeter.
Mass of Calorimeter /g A1: 43.5
Mass of Calorimeter + Cold Water /g A2: 94.2
Mass of Cold Water /g (A2 – A1)
Temperature of Cold Water °C (Therm 1) measured 21.3 corrected
Temperature of Hot Water °C (Therm 2) measured 45.2 corrected
Final Temperature of Water °C (Therm 1) measured 30.0 corrected
Mass of Calorimeter + Cold Water + Hot Water/g A3: 144.7
Mass of Hot Water /g (A3-A2)
The mcalib is 0.969 and bcalib is 2.0 C for both Thermometer 1 and Thermometer 2. B
Determine the heat capacity of the calorimeter.
Explanation / Answer
Mass of Cold Water = 94.2-43.5 = 50.7grams
T1 = 21.3 c
T2 = 45.2 C
Tf = 30
mass of hot water = 144.7-94.2 = 50.5 grams
heat lost by hot water = heat gained by cold water + heatcapacity of calorimeter*DT
(50.5*4.18*(45.2-30)) = (50.7*4.18*(30-21.3))+(x*(30-21.3))
x = heatcapacity of calorimeter = 0.156 kj/C
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