Data Analysis and Interpretation for Part II: Copper(11) Complex with Water and
ID: 948134 • Letter: D
Question
Data Analysis and Interpretation for Part II: Copper(11) Complex with Water and Hydroxide Ion How does the addition of 1 M HNO_3 affect the equilibrium?did the equilibrium shift toward the left or the right side? Explain. When HNO_3 and NaNO_3 are independently added to the equilibrium system, there is a difference in observed effect (tube 2 vs. tube 3). Identify the ion causing the equilibrium system to shift toward the left side. What is the role of this ion in shifting the equilibrium toward the left side? Did the order of addition of nitric acid and sodium hydroxide to the equilibrium system make any difference in shifting the equilibrium (tube 2, steps I and 2 vs. tube 4 step 5)? Why or why not? What reaction conditions appear to shift the position of equilibrium to make the complex with hydrox.de .on as complete as possible?Explanation / Answer
1. Addition of 1 M HNO3 a strong acid would shift the equilibrium towards left handside. More of Copper(II) hexaaqua complex would be formed here.
2. Adding HNO3 and NaNO3 independently to the equilibrium test tube causes equilibrium to shift towards left handside. This effect is caused by the ions H+ and Na+. The excess ion added to the system shifts the equilibrium back to the complex form.
3. Addition of NaOH first would shift the equilbrium towards right handside, whereas, addition of HNO3 would shift the equilibrium towards left handside. Thus the order in which they are added matters in the shift of equilibrium.
4. Addiiton of NaOH would shift the equilibrium towards formation of more copper(II) complex with hydroxide ion to completion.
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