Dashb × Inbox loncapa.phy.umassd.edu/capa-bin/orielly/capasbin 5 12pt) A chaged

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Dashb × Inbox loncapa.phy.umassd.edu/capa-bin/orielly/capasbin 5 12pt) A chaged particle is moving perpendicularly to a magnetic field B. Fil in the blank indicating the direction for the quantity missing in the table 1Z Force ty then enter +2-x-y in the compater (WITHOUT spaces between them) Use the diagram on the upper left for the directions of the various axes Submit Al Answers Answer 6. [2pt) A proton,t that s accelerated from rest through a potential of 1508 enters the velocity filter, consisting of a parallel-plate capacitor and a magnetic field, sbomm below the protons are not deflected (danore relativistic effects for high velocites DATA mg 167E 27kg he E fieldt t plany 2 1819 AYIWoured so thsat the protons are asot deflected"(goe Last Answer: 0 Answer tuchn es the porental coerg of the potestial. in order for the proton not to be deflected, the forces due to the tivo fields hare to cancel Hint: Yoù can ea

Explanation / Answer

m = mass of proton = 1.67 x 10-27 kg

v = speed gained = ?

V = potential difference = 15000 Volts

q = charge = 1.6 x 10-19 C

using conservation of energy

kinetic energy gained by proton = electric potential energy Lost

(0.5) m v2 = qV

v = sqrt(2qV/m)

v =  sqrt(2 (1.6 x 10-19) (15000)/(1.67 x 10-27))

v = 1.7 x 106 m/s

E = electric field = 3.1 x 105 N/C

B = magnetic field = ?

for the proton to pass undeflected

E = Bv

3.1 x 105 = B (1.7 x 106)

B = 0.18 T

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