Let\'s do a sample calculation of this type. A sample of an organic compound tha
ID: 947244 • Letter: L
Question
Let's do a sample calculation of this type. A sample of an organic compound that does not dissociate in water (i= 1.0) weighing 16.5 mg is dissolved in 10.0 mL of water at 24.5 Degree C on the fixed volume side of an osmometer. The solvent side is filled with distilled water. After the system comes to a steady state, the osmometer records an osmotic pressure of 224 m atm. What is the molar mass of the organic compound? pi = i MRT The expression for the morality of the compound is M = (1.65 x 10-2 9/Y)/(0.0100 L) where Y is the molar mass of the solute. Since we know i, pi, R and T (remember to convert the temperature to Kelvin), we can solve for Y. Set this up and solve for Y; then, enter the result below (use 2 sig figs in your answer). g/mol The organic compound in this example wasglucose.C_2H_120_6.Explanation / Answer
Osmotic pressure= 224matm =224*10-3 atm =iMRT
T= 24.5 deg.c =24.5+273.15= 297.65K R =0.08206 L.atm/mole.K
M =molairty= 1.65*10-2/(Y*0.01)
Y= Molar mass in g/mol
224*10-3 = 1.65*10-3/(Y*0.01)*0.08206*297.65
Y= 1.65*10-2*0.08206*297.65/(224*10-3*0.01)=179.92 g/mole
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