Let\'s do a bit of ATP accounting. This will be for arachidonic acid. This fatty
ID: 881622 • Letter: L
Question
Let's do a bit of ATP accounting. This will be for arachidonic acid. This fatty acid has 20 C atoms and 4 C=C double bonds.
NOTE: The presence of a double bond eliminates the need for FADH2 in one cycle of the beta-oxidation pathway, thus reducing ATP production by 1.5.
How many ATP equivalents are produced from the complete aerobic catabolism of arachidonic acid -- you'll have to do a calculation to get the answer. Remember to use 1.5 ATP produced per FADH2 and 2.5 ATP produced per NADH in oxphos.
It simplifies the calculation to remember that 10 ATP equivalents are produced in the processing of 1acetylCoA (through the CAC and oxidative phosphorylation).
A. 106
B. 128
C. 130
D. 134
E. 136
Explanation / Answer
Hello!
The arachidonic acid is conformed by 20 C, thus, it needs 9 cicles in the beta-oxidation cycle to produce 10 molecules of acetylCoA. Each cycle form 1 FADH2 an 1 NADH, but the arachidonic acid have 4 double bonds, that reason you should substract four FADH2 in whole process. Finally, each citric acid cycle, produce 10 ATP each one.
So, the correct anwser is C.
ATP equivalents NADH formed in 9 cycles of beta oxidation 9 x 2,5 = 22,5 FADH2 formed in 9 cycles of beta oxidation (9-4) 5 x 1,5 = 7,5 10 Citrid Acid Cicles 10 x 10 = 100 Total 130Related Questions
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