A.) The equilibrium constant for the reaction A( g ) B( g ) is 10 2 . A reaction

Question

A.) The equilibrium constant for the reaction A(g) B(g) is 102 . A reaction mixture initially contains [A] = 18.6 M and [B] = 0.0 M. Which statement is true at equilibrium?

B.) Determine the value of Kc for the following reaction if the equilibrium concentrations are as follows: [H2]eq = 0.14 M, [F 2]eq = 0.39 M, [HF]eq = 1.6 M.

H2(g) + F 2(g) 2 HF(g)

C.) The equilibrium constant is equal to 5.00 at 1300 K for the reaction:

2 SO2(g) + O2(g) 2 SO3(g).

If initial concentrations are [SO2] = 3.60 M, [O2] = 0.45 M, and [SO3] = 5.40 M, the system is

D.) The equilibrium constant, K p, equals 3.40 for the isomerization reaction:

cis-2-butene trans-2-butene.
If a flask initially contains 0.250 atm of cis-2-butene and 0.165 atm of trans-2-butene, what is the equilibrium pressure of each gas?

E.) Consider the reaction SO2(g) + NO2(g) NO(g) + SO3(g) at 460°C. What is the equilibrium concentration of the SO3 if the initial concentrations are [SO2] = [NO2] = 3.00 x 10-3 M and [NO] = [SO3] = 4.00 x 10-2 M? The value of the equilibrium constant for the reaction is 85.0 at 460°C.

The reaction mixture contains [A] = 18.4 M and [B] = 0.2 M. The reaction mixture contains [A] = 0.2 M and [B] = 18.4 M. The reaction mixture contains [A] = 1.0 M and [B] = 17.6 M. The reaction mixture contains [A] = 9.30 M and [B] = 9.30 M.

Explanation / Answer

A.)   A(g) B(g)

Initial 18.6 M 0 M

At equilibrium 18.6 - x x M

Equilibrium const = x/(18.6 - X) = 102

x = 18.4

[B] = 18.4 M

[A] = 0.2 M

B.)   H2(g) + F2(g) 2 HF(g)

Kc = [HF]eq2/[H2][F2]

= (1.6)2/(0.14)(0.39)

  Kc   = 46.9 = 47

C.)   2 SO2(g) + O2(g) 2 SO3(g).

above reaction equilibrium const for forward reaction is 5 and reverse reaction 1/5

forward reaction is more faster than reverse reaction

not at equilibrium and will shift to the right to achieve an equilibrium state.

D.)   cis-2-butene trans-2-butene   Kp = 3.4

initial 0.25 atm 0 atm

At equilibrium 0.25 - x atm x atm

Kp = x/(0.25 - x) = 3.4

x = 0.19 atm

  

trans-2-butene cis-2-butene Kp = 1/3.4 = 0.3

initial 0.165 atm 0 atm

ar equilibrium 0.165 - x atm x atm

  Kp = x/(0.165 - x) = 0.3

x = 0.04 atm

[cis-2-butene]eq = 0.25 - 0.19 + 0.04

= 0.1 atm

  [trans-2-butene]eq = 0.165 + 0.19 - 0.04

= 0.315 atm

E.)   

SO2(g) + NO2(g) NO(g) + SO3(g)

Initial 3*10-3 M 3*10-3 M 0 M 0 M

At equilibrium 3*10-3 - x  M 3*10-3 - x  M x M x M

Kc   = [NO][SO3]/[SO2][NO2] = 85

x2/(3*10-3 - x)2  = 85

84x2 - 510*10-3 x + 765*10-6 = 0

x = 2.196*10-3 M

  

NO(g) + SO3(g) SO2(g) + NO2(g)

Initial 4*10-2 M   4*10-2 M 0 M 0 M

At equilibrium 4*10-2 - x  M 4*10-2 - x  M x M x M

Kc   = [SO2][NO2]/[NO][SO3] = 1/85

x2/(4*10-2 - x)2  = 1/85

x = 3.91*10-3 M

[SO3]eq = 4*10-2 + 2.196*10-3 - 3.91*10-3

   = 3.8*10-2 m

  

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