A.) Given the demand, the cycle time for the production of the new train set =__
ID: 393154 • Letter: A
Question
A.) Given the demand, the cycle time for the production of the new train set =______ how many seconds? (round to one decimal place)B.) The theoretical minimum number of work stations is?? (round your response up to the next whole number)
C.) The theoretical minimum number of workstation=____ (round your response up to the next whole number)
D.) Using the longest operation time rule the assignment of tasks to workstation should be: (hint: Number workstations sequentially in terms of precedence relationships and combine any applicable tasks)
TASK, WORKSTATION NUMBER
A
STATION _____
B
STATION _____
C
STATION _____
D
STATION _____
E
STATION _____
F
STATION _____
Were you able to assign all the task to the theoretical, minimum number of workstations? ______
e.) the total idle time per cycle for the process-34 seconds (enter your response as a whole number)
f.) the efficiency of the assembly line with 5 workstations=_______%(enter your response as a percentage rounded to one decimal place.)
if one used 6 workstations instead of 5, the efficiency of the assembly line would be=_____%(enter your response as a percentage rounded to one decimal place.)
D.) The efficiency of the assembly line with 5 work stations equals??(one decimal place)
E.) if one used 6 work stations instead of 5, the efficiency of the assembly line would be what??(one decimal place) Homework: Ch 9 Assembly Line Balancing Score: 0 of 1 pt 8 of 11 (6 complete) Hw Score: 54.55%, 6 of 1 1 pt Problem 9.15 Question Help * The Action Toy Company has decided to 40-hour workweek: manufacture a new train set, the production of which is broken into six steps. The demand for the train is 4,600 units per train set, the 15 12 , D, E This exercise only contains parts b, c, d, e, and t b) Given the demand, the cycle time for the production of the now train set seconds (round your response to one decimal place)
Explanation / Answer
Given,
Demand = 4600 units / 40 hour week = 4600 units/144000 sec
Average throughput rate = 144000/4600 = 31.3 sec
So, cycle rate = 31.3 sec
Minimum number of workstations= sum of total task times / cycle time
=(22+30+14+15+12+28)/31.3 = 121/31.3 = 3.86 workstations = 4 workstations
c) Task Table
Task
Task time
Precedence
A
22
-
B
30
A
C
14
A
D
15
A
E
12
B,C
F
28
D,E
‘
The total station time is nothing but the cycle time. So, total station time of each station is 31.3 sec
In order of longest task time, tasks: B>F>A>D>C>E
Workstation 1:
First task =A (As B is dependent on A)
Time left= 31.3-22 = 9.3 sec
So, workstation 1: A
Workstation 2:
First task =B
Time left= 31.3-30 = 1.3 sec
So, workstation 2: B
Workstation 3:
First task =D
Time left= 31.3-15 = 16.3 sec
Second task =C
Time left= 16.3-14 = 2.3 sec
So, workstation 3: D->C
Workstation 4:
First task =E
Time left= 31.3-12 = 19.3 sec
So, workstation 4: E
Workstation 5:
First task =F
Time left= 31.3-28 = 3.3 sec
So, workstation 5: F
Work Station
Tasks
Workstation Time
Idle Time
1
A
22 sec
9.3 sec
2
B
30 sec
1.3 sec
3
D->C
29 sec
2.3 sec
4
E
12 sec
19.3 sec
5
F
28 sec
3.3 sec
Were you able to assign all the tasks to the theoretical minimum no of workstations: Yes
Total idle time = 9.3+1.3+2.3+19.3+3.3= 35.5 sec
Efficiency with 5 workstations = (sum of all tasks) / (no of workstations * Cycle time)
= (121)/ (5*31.3) = 0.773 or 77.3 %
Efficiency with 6 workstations = (sum of all tasks) / (no of workstations * Cycle time)
= (121)/ (6*31.3) = 0.644 or 64.4 %
Task
Task time
Precedence
A
22
-
B
30
A
C
14
A
D
15
A
E
12
B,C
F
28
D,E
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