The rate constant of a chemical reaction increased from 0.100 s1 to 2.60 s1 upon

Question

The rate constant of a chemical reaction increased from 0.100 s1 to 2.60 s1 upon raising the temperature from 25.0 C to 55.0 Part A T,-) Calculate the value of where T, is the initial temperature and T; is the final temperature. Express your answer numerically Submit Hints My Answers Give Up Review Par Part B calculate the value of In(%) where ki and k2 Calculate the value of In ( ) where ki and k2 correspond to the rate constants at the initial and ) where k, and A the final temperatures as defined in part A. Express your answer numerically. Hints My Answers Give Up Review Part Part C What is the activation energy of the reaction? Express your answer numerically in kilojoules per mole. kJ/mol

Explanation / Answer

Part A

1/T2 - 1/T1

=> 1/(273+55) - 1/(273+25)

=> 1/328 - 1/298

=> -3.06924 * 10^(-4) K^(-1)

Part B

ln(k1/k2) = ln(0.100/2.60) = -ln(26) = -3.258

Part C

Ea = R * -3.258/(-3.06924*10^(-4))

Ea = 88253.09 J/mol = 88.253 KJ/mol

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