4. The pressure of 4.0 L of nitrogen in a flexible container is decreased to one
ID: 944045 • Letter: 4
Question
4. The pressure of 4.0 L of nitrogen in a flexible container is decreased to one-half its original te temperature is increased to double the original temperature. The pressure, and its absolu volume is now a. 2.0L b.4.0 L c.8.0 L d. 16.0 L e.32.0L 5. How many moles of gas are in a gas sample occupying 0.250 L at 215 mmHg and 25°C? a. 0.00217 b. 0.00289 c.0.0345 d. 0.416 e. 1.27 6. At standard conditions, it was found that 1.17 L of a gas weighed 5.45 g. The gas is a. NHs b. HNF2 c. N2F4. d. NHs. e. NO2. 7. The following equation represents the complete combustion of ethane: At the same temperature and pressure, what is the maximum volume in liters of carbon dioxide that can be obtained from 50 L of C.Hs and 250 L of oxygen? (Hint: It is a limiting reactant problem) a. 25 b. 50 c. 100 d. 150 e. 200Explanation / Answer
Initial final
V1 = 4L V2
P1 =P P2 = P/2
T1 = T T2 = 2T
P1V1/T1 = P2V2/T2
P*4/T = P/2*V2/2T
V2 = 16L >>>> answer
5.PV = nRT
P =215mmHg = 215/760 = 0.2828atm
V = 0.25L
T= 25C = 25+273 = 298K
n = PV/RT
= 0.2828*0.25/0.0821*298
= 0.0707/24.47 = 0.002889 moles ... anser
6. standared conditions T = 273K
p = 1atm
v= 1.17L
W = 5.45gm
PV =nRT
n = W/M
PV = WRT/M
M = WRT/PV
= 5.45*0.0821*273/1*1.17 = 104.4 gm/mole that is N2F4 answer is C
7. 2C2H6 + 7O2 -----> 4CO2 + 6H2O
2*22.4 L C2H6 react with 7*22.4 L of O2
50L of C2H6 react with = 7*22.4*50/2*22.4 = 175L of O2 is required . So O2 is excess reagent
limiting reagent is C2H6
2 moles of C2H6 react with o2 to form 4 moles of CO2
50L of C2h6 react with O2 to form = 4*50/2 = 100L of Co2 answer is C
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