The Ka for the H2PO4–/HPO42– buffer is given by the equation: What is the pH of

Question

The Ka for the H2PO4–/HPO42– buffer is given by the equation:

What is the pH of a 3:2 mixture of H2PO4– to HPO42– at 0.010 M ionic strength? (See the table for the activity coefficients.)

What is the pH of a 3:2 mixture of H2PO4– to HPO42– at 0.010 M ionic strength?

The Ka for the H2PO4 HPObuffer is given by the equation: for the HPor HPo bulfer is given by 10-720 What is the pH of a 3.2 mixture of H2Po4to HPO See the table for the activity coefficients.) at 0.010 M ionic strength? Ionic Strength ( M) Number 0.005 0.010 0.0500.10 0.933 0.9140.860.83 Y0.7400.660 0.4450.355 HPO 0.928 0.902 0.82 0.775 H,PO

Explanation / Answer

pH = pKa + log)[base]/[acid])

Taking values from the table for activity coeficients of H2PO4- and HPO4^2- at 0.01 M ionic strength

pH = 7.20 + log(2 x 0.660/3 x 0.902)

       = 6.89 Is the pH of solution

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.