For Questions 1 & 2, consider the following system that has reached equilibrium,

Question

For Questions 1 & 2, consider the following system that has reached equilibrium, and then answer the questions and explain your reasoning. Note that C_2O_4^-2 is the oxalate ion. CdC_2O_4(s) + 4NH_3 (aq) = Cd(NH_3)_4^+2(aq) + C_2O_4^-2 (aq) If solid cadmium oxalate is added, the equilibrium will shift toward the reactants shift toward the products not shift at all produce some of the solid If NH_3(aq) is added the equilibrium will shift toward the reactants shift toward the products not shift at all cause some of the solid to be formed List a solution (that does NOT contain oxalate ion) which when added will cause the equilibrium to shift to the left to form some solid CdC_2O_4. Explain how your choice causes CdC_2O_4 to be formed.

Explanation / Answer

Cd(C2O4)(aq) <------> Cd2+(aq) + C2O42-(aq)

The solution could be Cd(SO4)2 which will furnish Cd2+ ions and thus , the eqb., will be shifted to left

Related Questions

Navigate

• Browse (All)
• Browse F
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.