Gibb\'s Free Energy Calculate ?G o for the following reaction at 25 o C using G

Question

Gibb's Free Energy

Calculate ?Go for the following reaction at 25o C using Go = ?Ho - T?So

Fe2O3 (s) + 3 H2 (g) 2 Fe (s) + 3 H2O (l)

Given:

                             ?Gof (kJ/mol)                              ?Hof (kJ/mol)                           So (J/k mol)

Fe2O3 (s)                   -743.6                                  -825.5                               87.40

H2 (s)                             0                                           0                                  130.6

Fe (s)                             0                                          0                                   27.3

H2O (l)                        -237.192                              -285.84                            69.94

Explanation / Answer

delta H0rkn = 3*delta Hf0 H2O + 2*delta Hf0 Fe - 3*delta Hf0 H2 - delta Hf0 Fe2O3 = -32.02 KJ/mole

delta S0rkn = 3*delta Sf0 H2O + 2*delta Sf0 Fe - 3*delta Sf0 H2 - delta Sf0 Fe2O3 = -214.78 J/mole

Now, delta G0rkn = delta H0rkn - T*delta S0rkn = -32020 - 298*(-214.78) = 31984.44 J/mole = 31.98444 kJ/mole

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