1.75 g of Thiamine Hydrochloride is dissolved in 8mL of water. 13 mL of 95% Etha

Question

1.75 g of Thiamine Hydrochloride is dissolved in 8mL of water. 13 mL of 95% Ethanol is added. 5 mL of NaOH is added. Finally, 5.3g of pure benzaldehyde is added and the solution is mixed thoroughly.
What is the theoretical yield of Benzoin? 1.75 g of Thiamine Hydrochloride is dissolved in 8mL of water. 13 mL of 95% Ethanol is added. 5 mL of NaOH is added. Finally, 5.3g of pure benzaldehyde is added and the solution is mixed thoroughly.
What is the theoretical yield of Benzoin?
What is the theoretical yield of Benzoin?

Explanation / Answer

2 C6H5CHO + C12H17ClN4OS ---> C14H12O2
(benzaldehyde + thiamine hydrochloride ---> benzoin)

Given, mass of thiamine hydrochloride = 1.75 g.

Molar mass of thiamine hydrochloride = 337.27 g/mol

Moles of thiamine hydrochloride = 5.2 x 10^-3 mol = 0.0052

Mass of benzaldehyde = 5.3 g

Molar mass of benzaldehyde = 106.121

Moles of benzaldehyde = 0.0499 mol

So, here, the limiting reagent is Thiamine hydrochloride, as the moles of thiamine hydrochloride are less.

From the chemical reaction, it is clear that 1 mol of benzoin is formed from 1 mol of thiamine hydrochloride.

So, moles of benzoin formed = 0.0052 mol

Molar mass of benzoin = 212.24 g/mol

Mass of benzoin = Moles x Molar mass = 0.0052 mol x 212.24 g/mol = 1.104 g

Thus, theoretical yield of Benzoin = 1.104 g

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