Percent recovery of a mixture. Hi all so I posted earlier about finding the perc

ID: 933568 • Letter: P

Question

Percent recovery of a mixture.

Hi all so I posted earlier about finding the percent composition of a mixture

The mixture is
Benzoic acid 95.61g
Anisole 243.48g
o-toluidine 296.16g
brought to volume with 2L of methylene chloride.,

which someone answered with this.

mass percent composition = mass of the solute /mass of solution*100

mass of methylene= 2L = 2000ml*1.33 = 2660 grams

density of methylene= 1.33 g/ml

mass of solution = 3295.25 grams

Benzoicacid = 95.61/3295.25*100 = 2.90%

Anisole = 243.48/3295.25*100 = 7.39%
o-toluidine = 296.16/3295.25*100 = 8.98%

in my lab we are supposed to calculate the percent composition of the stock above,

From this info i need the theoretical percent recovery of the 10 mL sample we used and the actual percent recovery of the 10 mL sample

here are the values i got for actual, im confused on what I need to do. pls help

Weight of o-toluidine = 2.11 g

Weight of benzoic acid = 0.05 g

Weight of anisole = 0.16 g

Total recovered mass = 2.32 g

10 ml of the sample solution [methylene chloride solution] * 1.33 g/mL = 13.3 grams of the solution

Benzoic acid is 2.90% of the mass of the solution ==> 0.0290 * 13.3 = 0.387 g = weight of benzoic acid

Anisole is 7.39% of the mass of the solution ==> 0.0739 * 13.3 g = 0.98287 g = weight of Anisole

O-toluidine is 8.98 % of the mass of the solution ==> 0.0898 * 13.3 g = 1.19434 g = weight of O-toluidine

These are the thereotical values of the components of the mixture

while the values in the end which you have for each component are actual values as you said

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