A pilot column breakthrough test has been performed using a phenolic wastewater

Question

A pilot column breakthrough test has been performed using a phenolic wastewater that has a phenol concentration of 400 mg/1 as TOC is to be treated by granular activated carbon. The isotherm is: The maximum value of x/m is 0.158 g TOC/g carbon, which occurs when C_c = Co = 0.400 g/1 TOC. Pertinent design data are : inside diameter 0.095 m, length 1.04 m. mass of carbon 2.98 kg liquid flowrate = 17.42 1/h. unit liquid flowrate = 0.679 l/s-m and packed carbon density = 400 g/1. The breakthrough data arc presented in the following table. Determine: The liquid flowrate in bed volumes per hour and the volume of liquid treated pa unit mass of carbon at an allowable breakthrough of 35 mg/ I TOC. The kinetic constants ki in Es-kg and in kg kg If this wastewater is to be treated by a fixed-bed granular carbon adsorption column for a wastewater flow of 220,000 1/d. The allowable breakthrough concentration is as in A above. The design column will have a unit liquid flowrate of 2.3 Vs-m The design procedure is to be the scale-up approach using the above mentioned values. Find the required column dimensions if the diameters arc in 15 cm increments. If the design procedure is to be the kinetic approach, find the column dimensions if the diameters are in 15 cm increments. Use the values of kt in l s-kg and qo in kg kg as determined in B above. The space (volumetric) loading for Parts A. B and C above in BODs/d-m^3

Explanation / Answer

To find the liquid flowrate,

BV, = area X length X (cu ft/ 1728 cu.in.)(7.48 gals/cu.ft)(3.785liters/gal) = liters

BV = ((3.75 in)2/4 X 41)(cu.ft/1728 cu.in)(7.48/cu.ft)(3.785 liters/gal) = 7.4193 liters

BV = Q/Qb

or Qb = Q/BV

= 17.42liter/hr/7.4193 liters

= 2.35 BV/hour

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