Link : https://www.youtube.com/watch?v=MG86IFZi_XM&feature=youtu.be Johnny had 5

Question

Link : https://www.youtube.com/watch?v=MG86IFZi_XM&feature=youtu.be

Johnny had 50.0 mL sample of 0.4360 M NH_4NO_3 that he diluted with water to a total volume of 250.0 mL. He has to figure out what is the ammonium nitrate concentration in the resulting solution? What equation is used? And what 2 pieces of glassware are used - explain what for Johnny has to make the 0.1510 M NaOH solution needed for his lab. If he uses a 100.00 mL volumetric flask, how many grams of NaOH does he need Explain how you would make this solution (so you will need to know grams of NaOH)

Explanation / Answer

1)   concentration of any compounds = millimoles / total volume

concentration of NH4NO3             = millimoles / total volume

                                                           = 0.4360 x 50 / (250 +50)

                                                            = 0.0727 M

NH4NO3 concentratiom = 0.0727 M

2)

NaOH molar mass = 40 g/mol

molarity of NaOH = 0.1510 M

volume of solution = 100 mL = 0.1 L

moles = molarity x volume = 0.1510 x 0.1 = 0.0152

moles = mass / molar mass

mass = moles x molar mas = 0.0151 x 40 = 0.604 g

NaOH needed = 0.604 g

Related Questions

Navigate

• Browse (All)
• Browse L
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.